Important SQL Queries Asked in Java Interviews

Important SQL Queries Asked in Java Interviews

·  Find the 3rd MAX salary in the emp table.

select distinct sal from emp e1 where 3 = (select count(distinct sal) from emp e2 where e1.sal <= e2.sal);

·  Find the 3rd MIN salary in the emp table.
select distinct sal from emp e1 where 3 = (select count(distinct sal) from emp e2where e1.sal >= e2.sal);

·  Select FIRST n records from a table.
select * from emp where rownum <= &n;

·  Select LAST n records from a table
select * from emp minus select * from emp where rownum <= (select count(*) - &n from emp);

·  List dept no., Dept name for all the departments in which there are no employees in the department.
select * from dept where deptno not in (select deptno from emp);
alternate solution:  select * from dept a where not exists (select * from emp b where a.deptno = b.deptno);
altertnate solution:  select empno,ename,b.deptno,dname from emp a, dept b where a.deptno(+) = b.deptno and empno is null; 

·  How to get 3 Max salaries ?
select distinct sal from emp a where 3 >= (select count(distinct sal) from emp b where a.sal <= b.sal) order by a.sal desc; 

·  How to get 3 Min salaries ?
select distinct sal from emp a  where 3 >= (select count(distinct sal) from emp b  where a.sal >= b.sal);

·  How to get nth max salaries ?
select distinct hiredate from emp a where &n =  (select count(distinct sal) from emp b where a.sal >= b.sal); 

·  Select DISTINCT RECORDS from emp table.
select * from emp a where  rowid = (select max(rowid) from emp b where  a.empno=b.empno); 

·  How to delete duplicate rows in a table?
delete from emp a where rowid != (select max(rowid) from emp b where  a.empno=b.empno); 

·  Count of number of employees in  department  wise.
select count(EMPNO), b.deptno, dname from emp a, dept b  where a.deptno(+)=b.deptno  group by b.deptno,dname; 

·   Suppose there is annual salary information provided by emp table. How to fetch monthly salary of each and every employee?

select ename,sal/12 as monthlysal from emp;

·  Select all record from emp table where deptno =10 or 40.

select * from emp where deptno=30 or deptno=10;

·  Select all record from emp table where deptno=30 and sal>1500.

select * from emp where deptno=30 and sal>1500;

·  Select  all record  from emp where job not in SALESMAN  or CLERK.

select * from emp where job not in ('SALESMAN','CLERK');

·  Select all record from emp where ename in 'BLAKE','SCOTT','KING'and'FORD'.

select * from emp where ename in('JONES','BLAKE','SCOTT','KING','FORD');

·  Select all records where ename starts with ‘S’ and its lenth is 6 char.

select * from emp where ename like'S_';

·  Select all records where ename may be any no of  character but it should end with ‘R’.

select * from emp where ename like'%R';

·  Count  MGR and their salary in emp table.

select count(MGR),count(sal) from emp;

·  In emp table add comm+sal as total sal  .

select ename,(sal+nvl(comm,0)) as totalsal from emp;

·  Select  any salary <3000 b="b" emp="emp" from="from" nbsp="nbsp" table.="table.">

select * from emp  where sal> any(select sal from emp where sal<3000 span="span">

·  Select  all salary <3000 b="b" emp="emp" from="from" nbsp="nbsp" table.="table.">

select * from emp  where sal> all(select sal from emp where sal<3000 span="span">

·  Select all the employee  group by deptno and sal in descending order.

select ename,deptno,sal from emp order by deptno,sal desc;

·  How can I create an empty table emp1 with same structure as emp?

Create table emp1 as select * from emp where 1=2;

·  How to retrive record where sal between 1000 to 2000?
Select * from emp where sal>=1000 And  sal<2000 span="span">

·  Select all records where dept no of both emp and dept table matches.
select * from emp where exists(select * from dept where emp.deptno=dept.deptno)

·  If there are two tables emp1 and emp2, and both have common record. How can I fetch all the recods but common records only once?
(Select * from emp) Union (Select * from emp1)

·  How to fetch only common records from two tables emp and emp1?
(Select * from emp) Intersect (Select * from emp1)

·   How can I retrive all records of emp1 those should not present in emp2?
(Select * from emp) Minus (Select * from emp1)

·  Count the totalsa  deptno wise where more than 2 employees exist.
SELECT  deptno, sum(sal) As totalsal
FROM emp
GROUP BY deptno HAVING COUNT(empno) > 2